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9x^2-62x+85=0
a = 9; b = -62; c = +85;
Δ = b2-4ac
Δ = -622-4·9·85
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-28}{2*9}=\frac{34}{18} =1+8/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+28}{2*9}=\frac{90}{18} =5 $
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